WebGeometry 13 Pre-Regional Mathemates If two tangents are drawn to a circle from an exterior point then \ ( ( i ) \) they subtend equal anges (ii) the angle between them is bisected by straight line joining the point and centre. Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions WebIn given figure, PQL and PRM are tangents to the circle with centre O at the points Q and R respectively. S is a point on the circle such that m ∠ SQL = 5 0 ∘ and ∠ SRM = 6 0 ∘. FInd …

PQL and PRM are tangents to a circle with centre O at points

WebApr 27, 2024 · In figure, if O is the centre of a circle, PQ is a chord and the tangent PR at P makes an angle of 500 with PQ, then ∠POQ is equal to (A) 100° (B) 80° (C) 90° (D) 75° Solution: (A) Given, ∠QPR = 50° We know that, the tangent at any point of a circle is perpendicular to the radius through the point of contact. ∴ ∠OPR = 90° ⇒ ∠OPQ + ∠QPR = … dd sao jose da bela vista

10 Mathematics Sa2 Sample Papers PDF Circle Triangle - Scribd

WebDec 15, 2016 · PQL and PRM are tangents to the circle with centre o at the points Q and R ,respectively and S is a point on the circle such that angle SQL=50 and angle SRM=60. Find angle QSR. Advertisement Expert-Verified Answer 138 people found it helpful santy2 SEE THE DIAGRAM ATTACHED Join Q to R WebFeb 7, 2014 · In given figure, PQL and PRM are tangents to the circle with centre O at the points Q and R respectively. S is a point on the circle such that SQL =50o and SRM=60o. … WebSolution: Given, PQR is the tangent at Q to a circle whose centre is O. AB is a chord parallel to PR. Also, ∠BQR = 70° We have to find the measure of angle AQB. We know that the radius of a circle is perpendicular to the tangent at the point of contact. So, ∠OQR = ∠OQP = 90° From the figure, ∠OQR = ∠OQB + ∠BQR 90° = ∠OQB + 70° ∠OQB = 90° - 70° bc kampenhout biljart