WebNov 2, 2006 · A person holds an 80N weight, 2 meters above the floor for 30 seconds, what is the power required in watts to do this? My answer: 4800watts Wg= -mgd Wg= -80N*2m Wg=-160J Wf=-Wg=160J 1watt=1J/s 30*160J/s=4800J/s=4800watts 10. The speed of a 4.0N hockey puck, sliding on the ice surface decreases at the rate of 0.61m/s^2. WebSep 30, 2024 · Solution: The weight of the block W=mg=300\, {\rm N} W = mg = 300N and the magnitude of the external force are given. (a) Again ''constant speed''. If there is a force equal in magnitude but opposite in direction of the external force, then the net force on the object is zero and, as a result, it moves at a constant speed.
6.2 Friction - University Physics Volume 1 OpenStax
http://mrkeefer.weebly.com/uploads/1/7/0/5/1705042/mechanical_advantage_ws.pdf WebThe normal force will be equal and opposite to the perpendicular gravity component so N = +mg*cos (Θ). To keep the block from sliding, you would then need to apply a horizontal force equal and opposite to the parallel gravity component so that force would be F = +mg*sin (Θ). Comment ( 6 votes) Upvote Downvote Flag more Show more... Brendan D. software house international uk
in a lab, a block weighing 80 n is attached to a spring …
WebFeb 28, 2024 · Take weight of block to be 100 N and coefficient of static friction at the contact Surface to be 0.4. 2. A block weighing 800 N has to rest on an incline of 30°. If the angle of limiting friction is 18°, Find the least and greatest force that need to be applied on the block, parallel to the plane so as to keep the block in equilibrium. 3. A ... WebMay 11, 2024 · In a lab, a block weighing 80 N is attached to a spring scale, and both are pulled to the right on a. In a lab, a block weighing 80 N is attached to a spring scale, and both are pulled to the right on a horizontal surface, as shown above. Friction between the block and the surface is negligible. WebOct 13, 2024 · Given that the weight of the body is 80 n. It is the product of mass and gravity of 10 m/s². Thus mass m = 80/10 = 8 kg. The scale reads a force of 32 Newton for the body weighing 8 Kg. Hence the acceleration can be calculated as follows: a … slow growing acers